Distance from Ruskin to Kalmthout
The shortest distance (air line) between Ruskin and Kalmthout is 4,618.29 mi (7,432.42 km).
How far is Ruskin from Kalmthout
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 16:13 (24.02.2025)
Kalmthout is located in Arr. Antwerpen, Belgium within 51° 22' 59.88" N 4° 28' 0.12" E (51.3833, 4.4667) coordinates. The local time in Kalmthout is 22:13 (24.02.2025)
The calculated flying distance from Kalmthout to Kalmthout is 4,618.29 miles which is equal to 7,432.42 km.
Ruskin, Florida, United States
Related Distances from Ruskin
Kalmthout, Arr. Antwerpen, Belgium