Distance from Ruskin to Koekelberg
The shortest distance (air line) between Ruskin and Koekelberg is 4,622.57 mi (7,439.31 km).
How far is Ruskin from Koekelberg
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 16:51 (24.02.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 22:51 (24.02.2025)
The calculated flying distance from Koekelberg to Koekelberg is 4,622.57 miles which is equal to 7,439.31 km.
Ruskin, Florida, United States
Related Distances from Ruskin
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium