Distance from Ruskin to Skanderborg
The shortest distance (air line) between Ruskin and Skanderborg is 4,737.57 mi (7,624.38 km).
How far is Ruskin from Skanderborg
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 06:56 (26.02.2025)
Skanderborg is located in Østjylland, Denmark within 56° 2' 30.12" N 9° 55' 30" E (56.0417, 9.9250) coordinates. The local time in Skanderborg is 12:56 (26.02.2025)
The calculated flying distance from Skanderborg to Skanderborg is 4,737.57 miles which is equal to 7,624.38 km.
Ruskin, Florida, United States
Related Distances from Ruskin
Skanderborg, Østjylland, Denmark