Distance from Ruston to Aleksandrow Kujawski
The shortest distance (air line) between Ruston and Aleksandrow Kujawski is 5,243.77 mi (8,439.04 km).
How far is Ruston from Aleksandrow Kujawski
Ruston is located in Louisiana, United States within 32° 31' 58.08" N -93° 21' 49.32" W (32.5328, -92.6363) coordinates. The local time in Ruston is 02:03 (19.05.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 09:03 (19.05.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,243.77 miles which is equal to 8,439.04 km.
Ruston, Louisiana, United States
Related Distances from Ruston
Aleksandrow Kujawski, Włocławski, Poland