Distance from Saint-Andre to Chateauneuf-les-Martigues
The shortest distance (air line) between Saint-Andre and Chateauneuf-les-Martigues is 512.57 mi (824.90 km).
How far is Saint-Andre from Chateauneuf-les-Martigues
Saint-Andre is located in Nord, France within 50° 39' 37.08" N 3° 2' 38.04" E (50.6603, 3.0439) coordinates. The local time in Saint-Andre is 16:43 (08.02.2025)
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 16:43 (08.02.2025)
The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 512.57 miles which is equal to 824.90 km.
Related Distances from Saint-Andre
Chateauneuf-les-Martigues, Bouches-du-Rhône, France