Distance from Saint-Andre-les-Vergers to Chateauneuf-les-Martigues
The shortest distance (air line) between Saint-Andre-les-Vergers and Chateauneuf-les-Martigues is 342.51 mi (551.21 km).
How far is Saint-Andre-les-Vergers from Chateauneuf-les-Martigues
Saint-Andre-les-Vergers is located in Aube, France within 48° 16' 46.92" N 4° 3' 14.04" E (48.2797, 4.0539) coordinates. The local time in Saint-Andre-les-Vergers is 21:29 (04.05.2025)
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 21:29 (04.05.2025)
The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 342.51 miles which is equal to 551.21 km.
Saint-Andre-les-Vergers, Aube, France
Related Distances from Saint-Andre-les-Vergers
Chateauneuf-les-Martigues, Bouches-du-Rhône, France