Distance from Saint Andrews to Aleksandrow Kujawski
The shortest distance (air line) between Saint Andrews and Aleksandrow Kujawski is 888.48 mi (1,429.86 km).
How far is Saint Andrews from Aleksandrow Kujawski
Saint Andrews is located in Clackmannanshire and Fife, United Kingdom within 56° 20' 25.44" N -3° 12' 16.2" W (56.3404, -2.7955) coordinates. The local time in Saint Andrews is 18:31 (25.02.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 19:31 (25.02.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 888.48 miles which is equal to 1,429.86 km.
Saint Andrews, Clackmannanshire and Fife, United Kingdom
Related Distances from Saint Andrews
Aleksandrow Kujawski, Włocławski, Poland