Distance from Sajoszentpeter to Vetraz-Monthoux
The shortest distance (air line) between Sajoszentpeter and Vetraz-Monthoux is 692.44 mi (1,114.37 km).
How far is Sajoszentpeter from Vetraz-Monthoux
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 21:28 (02.05.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 21:28 (02.05.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 692.44 miles which is equal to 1,114.37 km.
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary
Related Distances from Sajoszentpeter
Vetraz-Monthoux, Haute-Savoie, France