Distance from Salisbury to Aleksandrow Lodzki
The shortest distance (air line) between Salisbury and Aleksandrow Lodzki is 906.67 mi (1,459.15 km).
How far is Salisbury from Aleksandrow Lodzki
Salisbury is located in Wiltshire CC, United Kingdom within 51° 4' 12" N -2° 12' 36" W (51.0700, -1.7900) coordinates. The local time in Salisbury is 22:23 (10.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 23:23 (10.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 906.67 miles which is equal to 1,459.15 km.
Salisbury, Wiltshire CC, United Kingdom
Related Distances from Salisbury
Aleksandrow Lodzki, Łódzki, Poland