Distance from San Andres del Rabanedo to Chateauneuf-les-Martigues
The shortest distance (air line) between San Andres del Rabanedo and Chateauneuf-les-Martigues is 546.12 mi (878.89 km).
How far is San Andres del Rabanedo from Chateauneuf-les-Martigues
San Andres del Rabanedo is located in León, Spain within 42° 37' 0.12" N -6° 24' 0" W (42.6167, -5.6000) coordinates. The local time in San Andres del Rabanedo is 15:50 (17.11.2024)
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 15:50 (17.11.2024)
The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 546.12 miles which is equal to 878.89 km.
San Andres del Rabanedo, León, Spain
Related Distances from San Andres del Rabanedo
Chateauneuf-les-Martigues, Bouches-du-Rhône, France