Distance from San Angelo to Boortmeerbeek
The shortest distance (air line) between San Angelo and Boortmeerbeek is 5,152.02 mi (8,291.37 km).
How far is San Angelo from Boortmeerbeek
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 05:25 (24.02.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 12:25 (24.02.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 5,152.02 miles which is equal to 8,291.37 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Boortmeerbeek, Arr. Leuven, Belgium