Distance from San Angelo to Buggenhout
The shortest distance (air line) between San Angelo and Buggenhout is 5,137.77 mi (8,268.44 km).
How far is San Angelo from Buggenhout
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 18:41 (12.06.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 01:41 (13.06.2025)
The calculated flying distance from Buggenhout to Buggenhout is 5,137.77 miles which is equal to 8,268.44 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Buggenhout, Arr. Dendermonde, Belgium