Distance from San Angelo to Celakovice
The shortest distance (air line) between San Angelo and Celakovice is 5,550.89 mi (8,933.30 km).
How far is San Angelo from Celakovice
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 11:33 (25.02.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 18:33 (25.02.2025)
The calculated flying distance from Celakovice to Celakovice is 5,550.89 miles which is equal to 8,933.30 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Celakovice, Středočeský kraj, Czechia