Distance from San Angelo to Cesky Tesin
The shortest distance (air line) between San Angelo and Cesky Tesin is 5,701.52 mi (9,175.72 km).
How far is San Angelo from Cesky Tesin
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 11:34 (17.06.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 18:34 (17.06.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 5,701.52 miles which is equal to 9,175.72 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Cesky Tesin, Moravskoslezský kraj, Czechia