Distance from San Angelo to Courcelles
The shortest distance (air line) between San Angelo and Courcelles is 5,163.71 mi (8,310.18 km).
How far is San Angelo from Courcelles
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 03:44 (24.02.2025)
Courcelles is located in Arr. Charleroi, Belgium within 50° 27' 28.08" N 4° 22' 32.16" E (50.4578, 4.3756) coordinates. The local time in Courcelles is 10:44 (24.02.2025)
The calculated flying distance from Courcelles to Courcelles is 5,163.71 miles which is equal to 8,310.18 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Courcelles, Arr. Charleroi, Belgium