Distance from San Angelo to Korneuburg
The shortest distance (air line) between San Angelo and Korneuburg is 5,685.41 mi (9,149.79 km).
How far is San Angelo from Korneuburg
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 22:32 (23.02.2025)
Korneuburg is located in Wiener Umland/Nordteil, Austria within 48° 20' 43.08" N 16° 19' 59.16" E (48.3453, 16.3331) coordinates. The local time in Korneuburg is 05:32 (24.02.2025)
The calculated flying distance from Korneuburg to Korneuburg is 5,685.41 miles which is equal to 9,149.79 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Korneuburg, Wiener Umland/Nordteil, Austria