Distance from San Angelo to Oranienburg
The shortest distance (air line) between San Angelo and Oranienburg is 5,389.71 mi (8,673.90 km).
How far is San Angelo from Oranienburg
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 18:21 (08.03.2025)
Oranienburg is located in Oberhavel, Germany within 52° 45' 15.84" N 13° 14' 12.84" E (52.7544, 13.2369) coordinates. The local time in Oranienburg is 01:21 (09.03.2025)
The calculated flying distance from Oranienburg to Oranienburg is 5,389.71 miles which is equal to 8,673.90 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Oranienburg, Oberhavel, Germany