Distance from San Angelo to Osternienburg
The shortest distance (air line) between San Angelo and Osternienburg is 5,387.67 mi (8,670.61 km).
How far is San Angelo from Osternienburg
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 17:58 (08.03.2025)
Osternienburg is located in Anhalt-Bitterfeld, Germany within 51° 47' 60" N 12° 1' 0.12" E (51.8000, 12.0167) coordinates. The local time in Osternienburg is 00:58 (09.03.2025)
The calculated flying distance from Osternienburg to Osternienburg is 5,387.67 miles which is equal to 8,670.61 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Osternienburg, Anhalt-Bitterfeld, Germany