Distance from San Angelo to Oud-Turnhout
The shortest distance (air line) between San Angelo and Oud-Turnhout is 5,155.45 mi (8,296.89 km).
How far is San Angelo from Oud-Turnhout
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 16:47 (24.02.2025)
Oud-Turnhout is located in Arr. Turnhout, Belgium within 51° 19' 0.12" N 4° 58' 59.88" E (51.3167, 4.9833) coordinates. The local time in Oud-Turnhout is 23:47 (24.02.2025)
The calculated flying distance from Oud-Turnhout to Oud-Turnhout is 5,155.45 miles which is equal to 8,296.89 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Oud-Turnhout, Arr. Turnhout, Belgium