Distance from San Angelo to Verneuil-sur-Seine
The shortest distance (air line) between San Angelo and Verneuil-sur-Seine is 5,123.38 mi (8,245.29 km).
How far is San Angelo from Verneuil-sur-Seine
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 11:31 (01.03.2025)
Verneuil-sur-Seine is located in Yvelines, France within 48° 58' 46.92" N 1° 58' 26.04" E (48.9797, 1.9739) coordinates. The local time in Verneuil-sur-Seine is 18:31 (01.03.2025)
The calculated flying distance from Verneuil-sur-Seine to Verneuil-sur-Seine is 5,123.38 miles which is equal to 8,245.29 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Verneuil-sur-Seine, Yvelines, France