Distance from San Bruno to Aleksandrow Kujawski
The shortest distance (air line) between San Bruno and Aleksandrow Kujawski is 5,763.57 mi (9,275.58 km).
How far is San Bruno from Aleksandrow Kujawski
San Bruno is located in California, United States within 37° 37' 32.16" N -123° 34' 7.32" W (37.6256, -122.4313) coordinates. The local time in San Bruno is 19:01 (13.06.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 04:01 (14.06.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,763.57 miles which is equal to 9,275.58 km.
San Bruno, California, United States
Related Distances from San Bruno
Aleksandrow Kujawski, Włocławski, Poland