Distance from San Fernando to Aleksandrow Kujawski
The shortest distance (air line) between San Fernando and Aleksandrow Kujawski is 1,652.15 mi (2,658.88 km).
How far is San Fernando from Aleksandrow Kujawski
San Fernando is located in Cádiz, Spain within 36° 28' 0.12" N -7° 47' 60" W (36.4667, -6.2000) coordinates. The local time in San Fernando is 01:23 (15.12.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 01:23 (15.12.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 1,652.15 miles which is equal to 2,658.88 km.
Related Distances from San Fernando
Aleksandrow Kujawski, Włocławski, Poland