Distance from San Giovanni Rotondo to Cesky Tesin
The shortest distance (air line) between San Giovanni Rotondo and Cesky Tesin is 573.06 mi (922.25 km).
How far is San Giovanni Rotondo from Cesky Tesin
San Giovanni Rotondo is located in Foggia, Italy within 41° 42' 0" N 15° 43' 59.88" E (41.7000, 15.7333) coordinates. The local time in San Giovanni Rotondo is 10:00 (01.02.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 10:00 (01.02.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 573.06 miles which is equal to 922.25 km.
San Giovanni Rotondo, Foggia, Italy
Related Distances from San Giovanni Rotondo
Cesky Tesin, Moravskoslezský kraj, Czechia