Distance from San Giuliano Milanese to Alexandroupoli
The shortest distance (air line) between San Giuliano Milanese and Alexandroupoli is 891.39 mi (1,434.55 km).
How far is San Giuliano Milanese from Alexandroupoli
San Giuliano Milanese is located in Milano, Italy within 45° 23' 60" N 9° 16' 59.88" E (45.4000, 9.2833) coordinates. The local time in San Giuliano Milanese is 05:19 (07.02.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 06:19 (07.02.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 891.39 miles which is equal to 1,434.55 km.
San Giuliano Milanese, Milano, Italy