Distance from San Giuliano Milanese to Petersburg
The shortest distance (air line) between San Giuliano Milanese and Petersburg is 4,312.86 mi (6,940.88 km).
How far is San Giuliano Milanese from Petersburg
San Giuliano Milanese is located in Milano, Italy within 45° 23' 60" N 9° 16' 59.88" E (45.4000, 9.2833) coordinates. The local time in San Giuliano Milanese is 10:15 (11.12.2025)
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 04:15 (11.12.2025)
The calculated flying distance from Petersburg to Petersburg is 4,312.86 miles which is equal to 6,940.88 km.
San Giuliano Milanese, Milano, Italy
Related Distances from San Giuliano Milanese
Petersburg, Virginia, United States