Distance from San Jacinto to Cesky Tesin
The shortest distance (air line) between San Jacinto and Cesky Tesin is 6,057.03 mi (9,747.85 km).
How far is San Jacinto from Cesky Tesin
San Jacinto is located in California, United States within 33° 47' 49.2" N -117° 0' 30.24" W (33.7970, -116.9916) coordinates. The local time in San Jacinto is 02:47 (23.06.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 11:47 (23.06.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 6,057.03 miles which is equal to 9,747.85 km.
San Jacinto, California, United States
Related Distances from San Jacinto
Cesky Tesin, Moravskoslezský kraj, Czechia