Distance from San Leandro to Cesky Tesin
The shortest distance (air line) between San Leandro and Cesky Tesin is 5,938.27 mi (9,556.73 km).
How far is San Leandro from Cesky Tesin
San Leandro is located in California, United States within 37° 42' 26.64" N -123° 50' 24.36" W (37.7074, -122.1599) coordinates. The local time in San Leandro is 06:14 (26.04.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 15:14 (26.04.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 5,938.27 miles which is equal to 9,556.73 km.
San Leandro, California, United States
Related Distances from San Leandro
Cesky Tesin, Moravskoslezský kraj, Czechia