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      Distance from San Leandro to Clervaux

      The shortest distance (air line) between San Leandro and Clervaux is 5,603.23 mi (9,017.53 km).

      How far is San Leandro from Clervaux

      San Leandro is located in California, United States within 37° 42' 26.64" N -123° 50' 24.36" W (37.7074, -122.1599) coordinates. The local time in San Leandro is 21:48 (07.01.2026)

      Clervaux is located in Luxembourg, Luxembourg within 50° 2' 60" N 6° 1' 59.88" E (50.0500, 6.0333) coordinates. The local time in Clervaux is 06:48 (08.01.2026)

      The calculated flying distance from Clervaux to Clervaux is 5,603.23 miles which is equal to 9,017.53 km.

      San Leandro, California, United States

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      Clervaux, Luxembourg, Luxembourg

      Related Distances to Clervaux

      CitiesDistance
      Wiltz to Clervaux7.27 mi (11.70 km)
      Vianden to Clervaux11.16 mi (17.96 km)
      Diekirch to Clervaux13.71 mi (22.07 km)
      Redange-sur-Attert to Clervaux20.69 mi (33.30 km)
      Mersch to Clervaux20.94 mi (33.70 km)
      Echternach to Clervaux23.86 mi (38.41 km)
      Capellen to Clervaux28.09 mi (45.21 km)
      Luxembourg to Clervaux30.60 mi (49.25 km)
      Grevenmacher to Clervaux31.34 mi (50.44 km)
      Differdange to Clervaux37.01 mi (59.56 km)
      Remich to Clervaux37.97 mi (61.10 km)
      Esch-sur-Alzette to Clervaux38.29 mi (61.62 km)
      Dudelange to Clervaux39.22 mi (63.12 km)