Distance from San Leandro to Lyaskovets
The shortest distance (air line) between San Leandro and Lyaskovets is 6,500.96 mi (10,462.28 km).
How far is San Leandro from Lyaskovets
San Leandro is located in California, United States within 37° 42' 26.64" N -123° 50' 24.36" W (37.7074, -122.1599) coordinates. The local time in San Leandro is 10:07 (08.04.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 20:07 (08.04.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 6,500.96 miles which is equal to 10,462.28 km.
San Leandro, California, United States
Related Distances from San Leandro
Lyaskovets, Veliko Tarnovo, Bulgaria