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      Distance from San Leandro to Ritterhude

      The shortest distance (air line) between San Leandro and Ritterhude is 5,505.30 mi (8,859.93 km).

      How far is San Leandro from Ritterhude

      San Leandro is located in California, United States within 37° 42' 26.64" N -123° 50' 24.36" W (37.7074, -122.1599) coordinates. The local time in San Leandro is 11:14 (29.05.2025)

      Ritterhude is located in Osterholz, Germany within 53° 11' 9.96" N 8° 45' 28.8" E (53.1861, 8.7580) coordinates. The local time in Ritterhude is 20:14 (29.05.2025)

      The calculated flying distance from Ritterhude to Ritterhude is 5,505.30 miles which is equal to 8,859.93 km.

      San Leandro, California, United States

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      Ritterhude, Osterholz, Germany

      Related Distances to Ritterhude

      CitiesDistance
      Bremen to Ritterhude7.31 mi (11.77 km)
      Hamburg to Ritterhude57.04 mi (91.80 km)
      Hannover to Ritterhude69.36 mi (111.62 km)
      Bielefeld to Ritterhude81.04 mi (130.42 km)
      Munster to Ritterhude96.99 mi (156.10 km)
      Dortmund to Ritterhude127.57 mi (205.30 km)
      Bochum to Ritterhude134.54 mi (216.53 km)
      Gelsenkirchen to Ritterhude134.90 mi (217.10 km)
      Essen to Ritterhude140.73 mi (226.48 km)
      Duisburg to Ritterhude147.46 mi (237.32 km)
      Wuppertal to Ritterhude148.41 mi (238.85 km)
      Dusseldorf to Ritterhude158.71 mi (255.43 km)
      Cologne to Ritterhude173.31 mi (278.92 km)
      Bonn to Ritterhude183.57 mi (295.43 km)
      Leipzig to Ritterhude199.12 mi (320.45 km)
      Berlin to Ritterhude199.23 mi (320.64 km)
      Frankfurt to Ritterhude212.52 mi (342.02 km)
      Wiesbaden to Ritterhude215.58 mi (346.95 km)
      Mannheim to Ritterhude255.84 mi (411.73 km)
      Dresden to Ritterhude257.70 mi (414.73 km)
      Nuremberg to Ritterhude276.60 mi (445.15 km)
      Karlsruhe to Ritterhude289.00 mi (465.11 km)
      Stuttgart to Ritterhude305.16 mi (491.10 km)
      Augsburg to Ritterhude345.67 mi (556.31 km)
      Munich to Ritterhude369.93 mi (595.34 km)