Distance from San Leandro to Savigny-le-Temple
The shortest distance (air line) between San Leandro and Savigny-le-Temple is 5,580.59 mi (8,981.09 km).
How far is San Leandro from Savigny-le-Temple
San Leandro is located in California, United States within 37° 42' 26.64" N -123° 50' 24.36" W (37.7074, -122.1599) coordinates. The local time in San Leandro is 01:16 (03.06.2025)
Savigny-le-Temple is located in Seine-et-Marne, France within 48° 35' 2.76" N 2° 34' 59.52" E (48.5841, 2.5832) coordinates. The local time in Savigny-le-Temple is 10:16 (03.06.2025)
The calculated flying distance from Savigny-le-Temple to Savigny-le-Temple is 5,580.59 miles which is equal to 8,981.09 km.
San Leandro, California, United States
Related Distances from San Leandro
Savigny-le-Temple, Seine-et-Marne, France