Distance from San Martino Buon Albergo to Aleksandrow Kujawski
The shortest distance (air line) between San Martino Buon Albergo and Aleksandrow Kujawski is 618.49 mi (995.36 km).
How far is San Martino Buon Albergo from Aleksandrow Kujawski
San Martino Buon Albergo is located in Verona, Italy within 45° 25' 0.12" N 11° 5' 60" E (45.4167, 11.1000) coordinates. The local time in San Martino Buon Albergo is 06:12 (08.06.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 06:12 (08.06.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 618.49 miles which is equal to 995.36 km.
San Martino Buon Albergo, Verona, Italy
Related Distances from San Martino Buon Albergo
Aleksandrow Kujawski, Włocławski, Poland