Distance from San Sebastiano al Vesuvio to Lake Charles
The shortest distance (air line) between San Sebastiano al Vesuvio and Lake Charles is 5,696.58 mi (9,167.76 km).
How far is San Sebastiano al Vesuvio from Lake Charles
San Sebastiano al Vesuvio is located in Napoli, Italy within 40° 49' 59.88" N 14° 22' 0.12" E (40.8333, 14.3667) coordinates. The local time in San Sebastiano al Vesuvio is 23:14 (05.01.2026)
Lake Charles is located in Louisiana, United States within 30° 12' 3.6" N -94° 47' 20.04" W (30.2010, -93.2111) coordinates. The local time in Lake Charles is 16:14 (05.01.2026)
The calculated flying distance from Lake Charles to Lake Charles is 5,696.58 miles which is equal to 9,167.76 km.
San Sebastiano al Vesuvio, Napoli, Italy
Related Distances from San Sebastiano al Vesuvio
Lake Charles, Louisiana, United States