Distance from San Severino Marche to Alexander City
The shortest distance (air line) between San Severino Marche and Alexander City is 5,113.92 mi (8,230.06 km).
How far is San Severino Marche from Alexander City
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 12:43 (03.03.2025)
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 05:43 (03.03.2025)
The calculated flying distance from Alexander City to Alexander City is 5,113.92 miles which is equal to 8,230.06 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Alexander City, Alabama, United States