Distance from San Severino Marche to Asheboro
The shortest distance (air line) between San Severino Marche and Asheboro is 4,722.37 mi (7,599.92 km).
How far is San Severino Marche from Asheboro
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 19:40 (03.03.2025)
Asheboro is located in North Carolina, United States within 35° 42' 56.88" N -80° 11' 14.28" W (35.7158, -79.8127) coordinates. The local time in Asheboro is 13:40 (03.03.2025)
The calculated flying distance from Asheboro to Asheboro is 4,722.37 miles which is equal to 7,599.92 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Asheboro, North Carolina, United States