Distance from San Severino Marche to Aukstieji Paneriai
The shortest distance (air line) between San Severino Marche and Aukstieji Paneriai is 953.85 mi (1,535.08 km).
How far is San Severino Marche from Aukstieji Paneriai
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 05:13 (06.02.2025)
Aukstieji Paneriai is located in Vilniaus apskritis, Lithuania within 54° 36' 0" N 25° 11' 60" E (54.6000, 25.2000) coordinates. The local time in Aukstieji Paneriai is 06:13 (06.02.2025)
The calculated flying distance from Aukstieji Paneriai to Aukstieji Paneriai is 953.85 miles which is equal to 1,535.08 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Aukstieji Paneriai, Vilniaus apskritis, Lithuania