Distance from San Severino Marche to Austintown
The shortest distance (air line) between San Severino Marche and Austintown is 4,534.42 mi (7,297.44 km).
How far is San Severino Marche from Austintown
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 01:10 (04.03.2025)
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 19:10 (03.03.2025)
The calculated flying distance from Austintown to Austintown is 4,534.42 miles which is equal to 7,297.44 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Austintown, Ohio, United States