Distance from San Severino Marche to Bad Sassendorf
The shortest distance (air line) between San Severino Marche and Bad Sassendorf is 622.59 mi (1,001.96 km).
How far is San Severino Marche from Bad Sassendorf
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 09:49 (30.01.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 09:49 (30.01.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 622.59 miles which is equal to 1,001.96 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Bad Sassendorf, Soest, Germany