Distance from San Severino Marche to Bainbridge Island
The shortest distance (air line) between San Severino Marche and Bainbridge Island is 5,603.60 mi (9,018.13 km).
How far is San Severino Marche from Bainbridge Island
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 23:38 (03.03.2025)
Bainbridge Island is located in Washington, United States within 47° 38' 38.04" N -123° 27' 23.76" W (47.6439, -122.5434) coordinates. The local time in Bainbridge Island is 14:38 (03.03.2025)
The calculated flying distance from Bainbridge Island to Bainbridge Island is 5,603.60 miles which is equal to 9,018.13 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Bainbridge Island, Washington, United States