Distance from San Severino Marche to Bexley
The shortest distance (air line) between San Severino Marche and Bexley is 4,673.23 mi (7,520.84 km).
How far is San Severino Marche from Bexley
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 09:14 (04.03.2025)
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 03:14 (04.03.2025)
The calculated flying distance from Bexley to Bexley is 4,673.23 miles which is equal to 7,520.84 km.
San Severino Marche, Macerata, Italy