Distance from San Severino Marche to Bloomsburg
The shortest distance (air line) between San Severino Marche and Bloomsburg is 4,357.77 mi (7,013.15 km).
How far is San Severino Marche from Bloomsburg
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 10:09 (04.03.2025)
Bloomsburg is located in Pennsylvania, United States within 41° 0' 9.72" N -77° 32' 38.04" W (41.0027, -76.4561) coordinates. The local time in Bloomsburg is 04:09 (04.03.2025)
The calculated flying distance from Bloomsburg to Bloomsburg is 4,357.77 miles which is equal to 7,013.15 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Bloomsburg, Pennsylvania, United States