Distance from San Severino Marche to Chateaubriant
The shortest distance (air line) between San Severino Marche and Chateaubriant is 768.73 mi (1,237.16 km).
How far is San Severino Marche from Chateaubriant
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 19:31 (15.01.2025)
Chateaubriant is located in Loire-Atlantique, France within 47° 43' 0.84" N -2° 37' 26.04" W (47.7169, -1.3761) coordinates. The local time in Chateaubriant is 19:31 (15.01.2025)
The calculated flying distance from Chateaubriant to Chateaubriant is 768.73 miles which is equal to 1,237.16 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Chateaubriant, Loire-Atlantique, France