Distance from San Severino Marche to Chateauneuf-les-Martigues
The shortest distance (air line) between San Severino Marche and Chateauneuf-les-Martigues is 402.87 mi (648.35 km).
How far is San Severino Marche from Chateauneuf-les-Martigues
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 19:34 (15.01.2025)
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 19:34 (15.01.2025)
The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 402.87 miles which is equal to 648.35 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Chateauneuf-les-Martigues, Bouches-du-Rhône, France