Distance from San Severino Marche to Chestnut Ridge
The shortest distance (air line) between San Severino Marche and Chestnut Ridge is 4,251.70 mi (6,842.45 km).
How far is San Severino Marche from Chestnut Ridge
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 02:43 (05.03.2025)
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 20:43 (04.03.2025)
The calculated flying distance from Chestnut Ridge to Chestnut Ridge is 4,251.70 miles which is equal to 6,842.45 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Chestnut Ridge, New York, United States