Distance from San Severino Marche to Cuyahoga Falls
The shortest distance (air line) between San Severino Marche and Cuyahoga Falls is 4,563.79 mi (7,344.71 km).
How far is San Severino Marche from Cuyahoga Falls
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 10:17 (06.03.2025)
Cuyahoga Falls is located in Ohio, United States within 41° 9' 50.76" N -82° 28' 45.48" W (41.1641, -81.5207) coordinates. The local time in Cuyahoga Falls is 04:17 (06.03.2025)
The calculated flying distance from Cuyahoga Falls to Cuyahoga Falls is 4,563.79 miles which is equal to 7,344.71 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Cuyahoga Falls, Ohio, United States