Distance from San Severino Marche to Fairbanks
The shortest distance (air line) between San Severino Marche and Fairbanks is 4,898.53 mi (7,883.42 km).
How far is San Severino Marche from Fairbanks
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 03:08 (07.03.2025)
Fairbanks is located in Alaska, United States within 64° 50' 7.08" N -148° 20' 48.12" W (64.8353, -147.6533) coordinates. The local time in Fairbanks is 17:08 (06.03.2025)
The calculated flying distance from Fairbanks to Fairbanks is 4,898.53 miles which is equal to 7,883.42 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Fairbanks, Alaska, United States