Distance from San Severino Marche to Faribault
The shortest distance (air line) between San Severino Marche and Faribault is 4,884.42 mi (7,860.71 km).
How far is San Severino Marche from Faribault
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 02:27 (09.03.2025)
Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 19:27 (08.03.2025)
The calculated flying distance from Faribault to Faribault is 4,884.42 miles which is equal to 7,860.71 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Faribault, Minnesota, United States