Distance from San Severino Marche to Fergus Falls
The shortest distance (air line) between San Severino Marche and Fergus Falls is 4,891.17 mi (7,871.58 km).
How far is San Severino Marche from Fergus Falls
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 02:57 (09.03.2025)
Fergus Falls is located in Minnesota, United States within 46° 17' 7.44" N -97° 55' 27.12" W (46.2854, -96.0758) coordinates. The local time in Fergus Falls is 19:57 (08.03.2025)
The calculated flying distance from Fergus Falls to Fergus Falls is 4,891.17 miles which is equal to 7,871.58 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Fergus Falls, Minnesota, United States