Distance from San Severino Marche to Janow Lubelski
The shortest distance (air line) between San Severino Marche and Janow Lubelski is 675.27 mi (1,086.74 km).
How far is San Severino Marche from Janow Lubelski
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 12:53 (12.02.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 12:53 (12.02.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 675.27 miles which is equal to 1,086.74 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Janow Lubelski, Puławski, Poland