Distance from San Severino Marche to Lake Arbor
The shortest distance (air line) between San Severino Marche and Lake Arbor is 4,458.21 mi (7,174.80 km).
How far is San Severino Marche from Lake Arbor
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 13:58 (12.03.2025)
Lake Arbor is located in Maryland, United States within 38° 54' 37.8" N -77° 10' 10.56" W (38.9105, -76.8304) coordinates. The local time in Lake Arbor is 07:58 (12.03.2025)
The calculated flying distance from Lake Arbor to Lake Arbor is 4,458.21 miles which is equal to 7,174.80 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Lake Arbor, Maryland, United States